Make the route name error more helpful

As a developer I have no clue what "Invalid route name" means. If the
exception gives me a hint I might find it easier to figure out why my
route triggers this error.

Signed-off-by: Christoph Wurst <christoph@winzerhof-wurst.at>

diff --git a/lib/private/AppFramework/Routing/RouteConfig.php b/lib/private/AppFramework/Routing/RouteConfig.php
index c522d3436cab841a517780559f8bf37e051f1c56..2e9f15475b7491a319245e7df199155eaffeef4c 100644 (file)
--- a/lib/private/AppFramework/Routing/RouteConfig.php
+++ b/lib/private/AppFramework/Routing/RouteConfig.php
@@ -131,7 +131,7 @@ class RouteConfig {
 
                $split = explode('#', $name, 2);
                if (count($split) !== 2) {
-                       throw new \UnexpectedValueException('Invalid route name');
+                       throw new \UnexpectedValueException('Invalid route name: use the format foo#bar to reference FooController::bar');
                }
                list($controller, $action) = $split;
 

diff --git a/lib/private/AppFramework/Routing/RouteParser.php b/lib/private/AppFramework/Routing/RouteParser.php
index 8511ff9ee391abeb33c4c20de1c699c24c3cb575..4b1b36b7550e6a901af51c30a7199a5ba3ac2d78 100644 (file)
--- a/lib/private/AppFramework/Routing/RouteParser.php
+++ b/lib/private/AppFramework/Routing/RouteParser.php
@@ -94,7 +94,7 @@ class RouteParser {
 
                $split = explode('#', $name, 2);
                if (count($split) !== 2) {
-                       throw new \UnexpectedValueException('Invalid route name');
+                       throw new \UnexpectedValueException('Invalid route name: use the format foo#bar to reference FooController::bar');
                }
                list($controller, $action) = $split;