/* * Copyright (C) 2010, Google Inc. * and other copyright owners as documented in the project's IP log. * * This program and the accompanying materials are made available * under the terms of the Eclipse Distribution License v1.0 which * accompanies this distribution, is reproduced below, and is * available at http://www.eclipse.org/org/documents/edl-v10.php * * All rights reserved. * * Redistribution and use in source and binary forms, with or * without modification, are permitted provided that the following * conditions are met: * * - Redistributions of source code must retain the above copyright * notice, this list of conditions and the following disclaimer. * * - Redistributions in binary form must reproduce the above * copyright notice, this list of conditions and the following * disclaimer in the documentation and/or other materials provided * with the distribution. * * - Neither the name of the Eclipse Foundation, Inc. nor the * names of its contributors may be used to endorse or promote * products derived from this software without specific prior * written permission. * * THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND * CONTRIBUTORS "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, * INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES * OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE * ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT OWNER OR * CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, * SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT * NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; * LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER * CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, * STRICT LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) * ARISING IN ANY WAY OUT OF THE USE OF THIS SOFTWARE, EVEN IF * ADVISED OF THE POSSIBILITY OF SUCH DAMAGE. */ package org.eclipse.jgit.diff; /** * Equivalence function for a {@link org.eclipse.jgit.diff.Sequence} compared by * difference algorithm. *
* Difference algorithms can use a comparator to compare portions of two * sequences and discover the minimal edits required to transform from one * sequence to the other sequence. *
* Indexes within a sequence are zero-based.
*
* @param
* type of sequence the comparator supports.
*/
public abstract class SequenceComparator {
/**
* Compare two items to determine if they are equivalent.
*
* It is permissible to compare sequence {@code a} with itself (by passing
* {@code a} again in position {@code b}).
*
* @param a
* the first sequence.
* @param ai
* item of {@code ai} to compare.
* @param b
* the second sequence.
* @param bi
* item of {@code bi} to compare.
* @return true if the two items are identical according to this function's
* equivalence rule.
*/
public abstract boolean equals(S a, int ai, S b, int bi);
/**
* Get a hash value for an item in a sequence.
*
* If two items are equal according to this comparator's
* {@link #equals(Sequence, int, Sequence, int)} method, then this hash
* method must produce the same integer result for both items.
*
* It is not required for two items to have different hash values if they
* are are unequal according to the {@code equals()} method.
*
* @param seq
* the sequence.
* @param ptr
* the item to obtain the hash for.
* @return hash the hash value.
*/
public abstract int hash(S seq, int ptr);
/**
* Modify the edit to remove common leading and trailing items.
*
* The supplied edit {@code e} is reduced in size by moving the beginning A
* and B points so the edit does not cover any items that are in common
* between the two sequences. The ending A and B points are also shifted to
* remove common items from the end of the region.
*
* @param a
* the first sequence.
* @param b
* the second sequence.
* @param e
* the edit to start with and update.
* @return {@code e} if it was updated in-place, otherwise a new edit
* containing the reduced region.
*/
public Edit reduceCommonStartEnd(S a, S b, Edit e) {
// Skip over items that are common at the start.
//
while (e.beginA < e.endA && e.beginB < e.endB
&& equals(a, e.beginA, b, e.beginB)) {
e.beginA++;
e.beginB++;
}
// Skip over items that are common at the end.
//
while (e.beginA < e.endA && e.beginB < e.endB
&& equals(a, e.endA - 1, b, e.endB - 1)) {
e.endA--;
e.endB--;
}
return e;
}
}