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[UI] Hide consecutive additions and removals of the same label (#13315)

tags/v1.15.0-dev
Pedro Alves 3 år sedan
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8e368e7065
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1 ändrade filer med 25 tillägg och 2 borttagningar
  1. 25
    2
      routers/repo/issue.go

+ 25
- 2
routers/repo/issue.go Visa fil

@@ -2418,11 +2418,34 @@ func combineLabelComments(issue *models.Issue) {
c.AddedLabels[0] = c.Label
}
} else {
// Remove duplicated "added" and "removed" labels
// This way, adding and immediately removing a label won't generate a comment.
var appendingTo *[]*models.Label
var other *[]*models.Label

if removingCur {
prev.RemovedLabels = append(prev.RemovedLabels, c.Label)
appendingTo = &prev.RemovedLabels
other = &prev.AddedLabels
} else {
prev.AddedLabels = append(prev.AddedLabels, c.Label)
appendingTo = &prev.AddedLabels
other = &prev.RemovedLabels
}

appending := true

for i := 0; i < len(*other); i++ {
l := (*other)[i]
if l.ID == c.Label.ID {
*other = append((*other)[:i], (*other)[i+1:]...)
appending = false
break
}
}

if appending {
*appendingTo = append(*appendingTo, c.Label)
}

prev.CreatedUnix = c.CreatedUnix
issue.Comments = append(issue.Comments[:i], issue.Comments[i+1:]...)
continue

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